Integrand size = 30, antiderivative size = 167 \[ \int \frac {(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx=\frac {16 i a^2}{45 d e^4 \sqrt {e \sec (c+d x)} \sqrt {a+i a \tan (c+d x)}}-\frac {4 i a \sqrt {a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac {32 i a \sqrt {a+i a \tan (c+d x)}}{45 d e^4 \sqrt {e \sec (c+d x)}}-\frac {2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}} \]
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Time = 0.37 (sec) , antiderivative size = 167, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {3578, 3583, 3569} \[ \int \frac {(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx=\frac {16 i a^2}{45 d e^4 \sqrt {a+i a \tan (c+d x)} \sqrt {e \sec (c+d x)}}-\frac {32 i a \sqrt {a+i a \tan (c+d x)}}{45 d e^4 \sqrt {e \sec (c+d x)}}-\frac {4 i a \sqrt {a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac {2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}} \]
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Rule 3569
Rule 3578
Rule 3583
Rubi steps \begin{align*} \text {integral}& = -\frac {2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}}+\frac {(2 a) \int \frac {\sqrt {a+i a \tan (c+d x)}}{(e \sec (c+d x))^{5/2}} \, dx}{3 e^2} \\ & = -\frac {4 i a \sqrt {a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac {2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}}+\frac {\left (8 a^2\right ) \int \frac {1}{\sqrt {e \sec (c+d x)} \sqrt {a+i a \tan (c+d x)}} \, dx}{15 e^4} \\ & = \frac {16 i a^2}{45 d e^4 \sqrt {e \sec (c+d x)} \sqrt {a+i a \tan (c+d x)}}-\frac {4 i a \sqrt {a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac {2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}}+\frac {(16 a) \int \frac {\sqrt {a+i a \tan (c+d x)}}{\sqrt {e \sec (c+d x)}} \, dx}{45 e^4} \\ & = \frac {16 i a^2}{45 d e^4 \sqrt {e \sec (c+d x)} \sqrt {a+i a \tan (c+d x)}}-\frac {4 i a \sqrt {a+i a \tan (c+d x)}}{15 d e^2 (e \sec (c+d x))^{5/2}}-\frac {32 i a \sqrt {a+i a \tan (c+d x)}}{45 d e^4 \sqrt {e \sec (c+d x)}}-\frac {2 i (a+i a \tan (c+d x))^{3/2}}{9 d (e \sec (c+d x))^{9/2}} \\ \end{align*}
Time = 1.58 (sec) , antiderivative size = 113, normalized size of antiderivative = 0.68 \[ \int \frac {(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx=\frac {a (\cos (d x)-i \sin (d x)) (-81 i \cos (c+d x)+5 i \cos (3 (c+d x))-54 \sin (c+d x)+10 \sin (3 (c+d x))) (\cos (c+2 d x)+i \sin (c+2 d x)) \sqrt {a+i a \tan (c+d x)}}{90 d e^4 \sqrt {e \sec (c+d x)}} \]
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Time = 9.89 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.57
method | result | size |
default | \(\frac {2 \cos \left (d x +c \right ) \left (\tan \left (d x +c \right )-i\right ) a \sqrt {a \left (1+i \tan \left (d x +c \right )\right )}\, \left (10 i \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )-5 \left (\cos ^{3}\left (d x +c \right )\right )-16 i \sin \left (d x +c \right )+24 \cos \left (d x +c \right )\right )}{45 d \sqrt {e \sec \left (d x +c \right )}\, e^{4}}\) | \(95\) |
risch | \(-\frac {i a \sqrt {\frac {a \,{\mathrm e}^{2 i \left (d x +c \right )}}{{\mathrm e}^{2 i \left (d x +c \right )}+1}}\, \left (5 \,{\mathrm e}^{4 i \left (d x +c \right )}+135+12 \cos \left (2 d x +2 c \right )+42 i \sin \left (2 d x +2 c \right )\right )}{180 e^{4} \sqrt {\frac {e \,{\mathrm e}^{i \left (d x +c \right )}}{{\mathrm e}^{2 i \left (d x +c \right )}+1}}\, d}\) | \(99\) |
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Time = 0.25 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.62 \[ \int \frac {(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx=\frac {{\left (-5 i \, a e^{\left (8 i \, d x + 8 i \, c\right )} - 32 i \, a e^{\left (6 i \, d x + 6 i \, c\right )} - 162 i \, a e^{\left (4 i \, d x + 4 i \, c\right )} - 120 i \, a e^{\left (2 i \, d x + 2 i \, c\right )} + 15 i \, a\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {\frac {e}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (-\frac {3}{2} i \, d x - \frac {3}{2} i \, c\right )}}{180 \, d e^{5}} \]
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Timed out. \[ \int \frac {(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx=\text {Timed out} \]
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Time = 0.42 (sec) , antiderivative size = 160, normalized size of antiderivative = 0.96 \[ \int \frac {(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx=\frac {{\left (-5 i \, a \cos \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 15 i \, a \cos \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) - 27 i \, a \cos \left (\frac {5}{3} \, \arctan \left (\sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ), \cos \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right )\right )\right ) - 135 i \, a \cos \left (\frac {1}{3} \, \arctan \left (\sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ), \cos \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right )\right )\right ) + 5 \, a \sin \left (\frac {9}{2} \, d x + \frac {9}{2} \, c\right ) + 15 \, a \sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ) + 27 \, a \sin \left (\frac {5}{3} \, \arctan \left (\sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ), \cos \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right )\right )\right ) + 135 \, a \sin \left (\frac {1}{3} \, \arctan \left (\sin \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right ), \cos \left (\frac {3}{2} \, d x + \frac {3}{2} \, c\right )\right )\right )\right )} \sqrt {a}}{180 \, d e^{\frac {9}{2}}} \]
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\[ \int \frac {(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx=\int { \frac {{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {3}{2}}}{\left (e \sec \left (d x + c\right )\right )^{\frac {9}{2}}} \,d x } \]
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Time = 6.54 (sec) , antiderivative size = 125, normalized size of antiderivative = 0.75 \[ \int \frac {(a+i a \tan (c+d x))^{3/2}}{(e \sec (c+d x))^{9/2}} \, dx=-\frac {a\,\sqrt {\frac {e}{\cos \left (c+d\,x\right )}}\,\sqrt {\frac {a\,\left (\cos \left (2\,c+2\,d\,x\right )+1+\sin \left (2\,c+2\,d\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,c+2\,d\,x\right )+1}}\,\left (-42\,\sin \left (c+d\,x\right )-47\,\sin \left (3\,c+3\,d\,x\right )-5\,\sin \left (5\,c+5\,d\,x\right )+\cos \left (c+d\,x\right )\,282{}\mathrm {i}+\cos \left (3\,c+3\,d\,x\right )\,17{}\mathrm {i}+\cos \left (5\,c+5\,d\,x\right )\,5{}\mathrm {i}\right )}{360\,d\,e^5} \]
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